2^2*2^n=(2^4)^3

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Solution for 2^2*2^n=(2^4)^3 equation: 



2^2*2^n=(2^4)^3

We move all terms to the left:

2^2*2^n-((2^4)^3)=0

determiningTheFunctionDomain
2^2*2^n-2^4^3=0

We add all the numbers together, and all the variables

2^2*2^n+19-1.84467440737E=0

Wy multiply elements

4n^3+19-1.84467440737E=0

We do not support enpression: n^3

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